(1+2b^2)/b - solution

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Solution for (1+2b^2)/b equation:

D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

(2*b^2+1)/b = 0

2*b^2 = -1 // : 2

b^2 = -1/2

b belongs to the empty set

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